SOLUTION: Suppose that N=85^200 + 120^200. Find the remainder when you divide N by 7

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Question 1175733: Suppose that N=85^200 + 120^200. Find the remainder when you divide N by 7
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
use calculator

N%2F7=+%2885%5E200+%2B+120%5E200%29%2F7
= you will get a 415 digits number divided by 7
9798309862755787391920449849945011486669103430323507536675409892593859701036903676797348839745282193919246573753972946611903343672345940418716220825984959353725067289732036865564721964309176591673859280347614851750169703486329874059694409756321920195582508989002795927699772619119078618649282895208734048031656233978289822519296035605590199211305084111990845427668727161346356418254137971806423073368413107735770089 ++2%2F7

remainder:2%2F7

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Suppose that N=85^200 + 120^200. Find the remainder when you divide N by 7
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Notice that  85 = 12*7 + 1  gives the remainder 1, when divided by 7.


Hence, the number 85 in any integer positive degree gives the remainder 1, when divided by 7.


In particular,  85^200  gives the remainder 1, when divided by 7.




Next, notice that  120 = 17*7 + 1.


The same arguments prove that  120^200  gives the remainder 1, when divided by 7.


So the ANSWER to the problem's question is 1 + 1 = 2.


Solved.


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How @MathLover1 treats the problem,  shows that she  NEITHER  understands the subject
NOR  knows how to approach the question.