SOLUTION: Please help me solve this problem A researcher is investigating a specimen of bacteria. She finds that the 1000 bacteria grew o 2,048,000 in 60 hours. How fast does the bacteria

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Question 1169677: Please help me solve this problem
A researcher is investigating a specimen of bacteria. She finds that the 1000 bacteria grew o 2,048,000 in 60 hours. How fast does the bacteria (a) double? (b) quadruple?

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

Notice that  2048000%2F1000 = 2048 = 2%5E11.



It means that 60 hours = 11 doubling periods.


Hence, one doubling period is  60%2F11 = 5 5%2F11  hours.


And a quadruple period is twice of it, i.e.  120%2F11 hours = 10 10%2F11 hours.

Solved.

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See the lesson
    - Radioactive decay problems
in this site - - - to make your horizon   W I D E R.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.