SOLUTION: how would i do the problem 3x^2+4x=7

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: how would i do the problem 3x^2+4x=7      Log On


   



Question 115031: how would i do the problem 3x^2+4x=7
Found 2 solutions by MathLover1, jim_thompson5910:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

3x%5E2%2B4x=7……. Write it in the standard form ax%5E2+%2Bbx+%2Bc+=+0++

3x%5E2+%2B+4x+%96+7+=+0…….use quadratic formula to solve
x%5B1%2C2%5D=%28-b+%2B-+sqrt+%28b%5E2+-4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29

x%5B1%2C2%5D=%28-4+%2B-+sqrt+%284%5E2+-4%2A3%2A%28-7%29+%29%29+%2F+%282%2A3%29
x%5B1%2C2%5D=%28-4+%2B-+sqrt+%2816+%2B+84%29%29+%2F+6
x%5B1%2C2%5D=%28-4+%2B-+sqrt+%28100%29%29+%2F+6

x%5B1%2C2%5D=%28-4+%2B-++10%29+%2F+6

x%5B1%5D=%28-4+%2B++10%29+%2F+6
x%5B1%5D=+6+%2F+6
x%5B1%5D=+1

x%5B2%5D=%28-4+-++10%29+%2F+6
x%5B2%5D=+-14+%2F+6…….divide by 2
x%5B2%5D=+-7+%2F+3
x%5B2%5D=+-2.33

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2%2B4x=7 Start with the given equation


3x%5E2%2B4x-7=0 Move all of the terms to the left side


Let's use the quadratic formula to solve for x:


Starting with the general quadratic

ax%5E2%2Bbx%2Bc=0

the general solution using the quadratic equation is:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29



So lets solve 3%2Ax%5E2%2B4%2Ax-7=0 ( notice a=3, b=4, and c=-7)




x+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A3%2A-7+%29%29%2F%282%2A3%29 Plug in a=3, b=4, and c=-7



x+=+%28-4+%2B-+sqrt%28+16-4%2A3%2A-7+%29%29%2F%282%2A3%29 Square 4 to get 16



x+=+%28-4+%2B-+sqrt%28+16%2B84+%29%29%2F%282%2A3%29 Multiply -4%2A-7%2A3 to get 84



x+=+%28-4+%2B-+sqrt%28+100+%29%29%2F%282%2A3%29 Combine like terms in the radicand (everything under the square root)



x+=+%28-4+%2B-+10%29%2F%282%2A3%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



x+=+%28-4+%2B-+10%29%2F6 Multiply 2 and 3 to get 6

So now the expression breaks down into two parts

x+=+%28-4+%2B+10%29%2F6 or x+=+%28-4+-+10%29%2F6

Lets look at the first part:

x=%28-4+%2B+10%29%2F6

x=6%2F6 Add the terms in the numerator
x=1 Divide

So one answer is
x=1



Now lets look at the second part:

x=%28-4+-+10%29%2F6

x=-14%2F6 Subtract the terms in the numerator
x=-7%2F3 Divide

So another answer is
x=-7%2F3

So our solutions are:
x=1 or x=-7%2F3

Notice when we graph 3%2Ax%5E2%2B4%2Ax-7, we get:

+graph%28+500%2C+500%2C+-17%2C+11%2C+-17%2C+11%2C3%2Ax%5E2%2B4%2Ax%2B-7%29+

and we can see that the roots are x=1 and x=-7%2F3. This verifies our answer