SOLUTION: Hopefully simple question that I just can't find the answer to... I have y=ax^b. I know y, a, and b, I want to solve for x. Thank you!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Hopefully simple question that I just can't find the answer to... I have y=ax^b. I know y, a, and b, I want to solve for x. Thank you!      Log On


   

Question 1150248: Hopefully simple question that I just can't find the answer to...
I have y=ax^b. I know y, a, and b, I want to solve for x.
Thank you!
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

y = a%2Ax%5Eb   ================>


y%2Fa = x%5Eb


x = %28y%2Fa%29%5E%281%2Fb%29.      ANSWER

Solved.


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Comment from student :  Thank you!  It’s been  35  years since college and it just wasn’t coming to me.
I was over complicating it,  trying to use logs and LN.  I did a face palm when I saw your simple solution!  Thanks again!
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My response :   I like your comment very much !   Have a nice day !