SOLUTION: Find the slope of the line tangent to the following at point where x = 2: 〖f(x)=e〗^(-0.1x^2+2x-3)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Find the slope of the line tangent to the following at point where x = 2: 〖f(x)=e〗^(-0.1x^2+2x-3)       Log On


   

Question 1150071: Find the slope of the line tangent to the following at point where x = 2:
〖f(x)=e〗^(-0.1x^2+2x-3)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of the line tangent to the following at point where x = 2:
〖f(x)=e〗^(-0.1x^2+2x-3)
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f%28x%29+=+e%5E%28-0.1x%5E2%2B2x-3%29
f'(x) = e%5E%28-0.1x%5E2%2B2x-3%29%2A%28-0.2x+%2B+2%29
f'(x) = %28-0.2x+%2B+2%29%2Ae%5E%28-0.1x%5E2%2B2x-3%29
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Sub 2 for x