SOLUTION: The number of bacteria in a certain culture increased from 500 to 1000 between 7:00 A.M. and 9:00 A.M. Assuming growth is exponential, the number f(t) of bacteria t hours after 7:0

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The number of bacteria in a certain culture increased from 500 to 1000 between 7:00 A.M. and 9:00 A.M. Assuming growth is exponential, the number f(t) of bacteria t hours after 7:0      Log On


   

Question 1147952: The number of bacteria in a certain culture increased from 500 to 1000 between 7:00 A.M. and 9:00 A.M. Assuming growth is exponential, the number f(t) of bacteria t hours after 7:00 A.M. is given by f(t) = 500(2)t/2.
Estimate the number of bacteria in the culture at 8:00 A.M., 10:00 A.M., and 11:00 A.M. (Round your answers to the nearest whole number.)


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Use "^" (shift-6) to denote exponentiation -- "500(2)^(t/2)" instead of "500(2)t/2".

t is the number of hours after 7:00 A.M. So for 8 am t=1; for 10 am t=3; and for 11 am t=4.

Use a calculator to plug in those values of t and round as directed....