SOLUTION: If log(2) = r, log(5) = s, and log(6) = t, find log({{{5/3}}}) in terms of r,s, and/or t.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: If log(2) = r, log(5) = s, and log(6) = t, find log({{{5/3}}}) in terms of r,s, and/or t.      Log On


   



Question 113671: If log(2) = r, log(5) = s, and log(6) = t,
find log(5%2F3) in terms of r,s, and/or t.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
If log(2) = r, log(5) = s, and log(6) = t,
find log(5%2F3) in terms of r,s, and/or t.
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log(5%2F3)

use a law of logarithms to rewrite that as

log(5%2F3) = log(5) - log(3)

And since log(5) = s, we have

log(5%2F3) = s - log(3)

Now we have to find log(3)

Rewrite write 3 as 6%2F2

log(5%2F3) = s - log(6%2F2)

Put brackets around log(6%2F2)

log(5%2F3) = s - [log(6%2F2)]

Use a rule of logs to write log(6%2F2%29) as log(6) - log(2)

log(5%2F3) = s - [log(6) - log(2)]

Remove the brackets by changing signs since it is
preceded by a minus sign:

log(5%2F3) = s - log(6) + log(2)

Since we are told that log(6) = t and log(2) = r,
we substitute these and end up with

log(5%2F3) = s - t + r

Edwin