SOLUTION: A radioisotope is used as a power source for a satellite. The power output is given by the equation P=50e^-t/250, where P is the power in watts and t is the time in days.
a). Find
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-> SOLUTION: A radioisotope is used as a power source for a satellite. The power output is given by the equation P=50e^-t/250, where P is the power in watts and t is the time in days.
a). Find
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Question 113540This question is from textbook Glencoe Algebra 2
: A radioisotope is used as a power source for a satellite. The power output is given by the equation P=50e^-t/250, where P is the power in watts and t is the time in days.
a). Find the power available after 100 days
b). Ten watts of power are required to operate the equipment in the satellite. How long can the satellite continue to operate? This question is from textbook Glencoe Algebra 2
You can put this solution on YOUR website! A radioisotope is used as a power source for a satellite. The power output is given by the equation P=50e^-t/250, where P is the power in watts and t is the time in days.
a). Find the power available after 100 days
P(100) = 50e^(-100/250)
P(100) = 50*0.6703200...
P(100) = 33.5160...
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b). Ten watts of power are required to operate the equipment in the satellite. How long can the satellite continue to operate?
10 = 50e^(-t/250)
0.2 = e^(-t/250)
Take the natural log of both sides to get:
-t/250 = ln0.2
-t/250 = -1.6094379...
t = 402.359.. days
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Cheers,
Stan H.
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