SOLUTION: If n and p are positive integers such that 8(2^p) = 4^n , what is n in terms of p?

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Question 1105187: If n and p are positive integers such that 8(2^p) = 4^n , what is n in terms of p?
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
8(2^p) = 4^n
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Note rewrite above as
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2^(3+p) = 4^n
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now we can write
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4^n = 2^(3+p)
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take logarithm base 4 of both sides
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n = ln ( 2^(3+p) ) / ln (4) for 2^p > 0 and ln is the natural logarithm
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