SOLUTION: The function is an exponential one if it is in the form: f(x)=A^x where A is not equal to 1, and A>0. The question is why A must be >0 and A is not equal to 1?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The function is an exponential one if it is in the form: f(x)=A^x where A is not equal to 1, and A>0. The question is why A must be >0 and A is not equal to 1?      Log On


   

Question 1102297: The function is an exponential one if it is in the form: f(x)=A^x where A is not equal to 1, and A>0. The question is why A must be >0 and A is not equal to 1?
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
If A = 1, the function does not vary with x. The function would simply be f(x) = 1, since 1 raised to any power is still 1.
If A < 0, then for integer values of x, the even powers give positive f(x) and the odd powers give negative f(x),
and for non-integer values such as x=1.5, the function is undefined.