SOLUTION: I'm stuck on a logarithm problem.
The original problem is log5(the 5 is superscript)square root of x = square root of log(x).
i've gotten as far as logx^(1/5)=square root (l
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-> SOLUTION: I'm stuck on a logarithm problem.
The original problem is log5(the 5 is superscript)square root of x = square root of log(x).
i've gotten as far as logx^(1/5)=square root (l
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Question 109935: I'm stuck on a logarithm problem.
The original problem is log5(the 5 is superscript)square root of x = square root of log(x).
i've gotten as far as logx^(1/5)=square root (log(x)) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! log5(the 5 is superscript)square root of x = square root of log(x).
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log(x^(1/5)) = log(x^(1/2))
Comment: That doesn't seem to make any sense.
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Cheers,
Stan H.
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