SOLUTION: From 1991 through 1995, the number of computers per 1000 people worldwide can be modeled by C = 25.2(1.15)t, where is the is the number of years since 1991. The initial amount is

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: From 1991 through 1995, the number of computers per 1000 people worldwide can be modeled by C = 25.2(1.15)t, where is the is the number of years since 1991. The initial amount is       Log On


   



Question 1094716: From 1991 through 1995, the number of computers per 1000 people worldwide can be modeled by C = 25.2(1.15)t, where is the is the number of years since 1991.
The initial amount is
The growth factor is ___________
The annual percent increase is ___________
%
If the trend continues, the number of computers per 1000 people worldwide in 2000 is _____________
. Round to two decimal places,

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

Clearly, since this is an exponential growth problem, the formula is supposed to be
25.2%281.15%29%5Et
and not
25.2%281.15%29t

In an exponential formula in that standard form, the 25.2 is the initial value and the 1.15 is the periodic growth factor. "Initial value" needs no explanation. "Growth factor" is what the current value gets multiplied by each period. With a growth factor of 1.15, it means the value for one year gets multiplied by 1.15 to get the value for the next year. Multiplying by 1.15 is the same as multiplying by 115%; since 115% is 100% plus 15%, that growth factor indicates that the value is growing by 15% each year.

So
... the initial amount is 25.2 (number of computers per 1000 people worldwide in 1991);
... the growth factor is 1.15, or 115%; and
... the annual percent increase is 15%.

To find the number of computers per 1000 people worldwide in 2000, since 2000 is 9 years after the initial measurement, evaluate the given function for t=9. Note that the form of the exponential function indicates that the initial value is multiplied by the growth factor 9 times (once each year) to get the value of the function 9 years after the start.

25.2%281.15%29%5E9+=+88.65