Tutors Answer Your Questions about Exponential-and-logarithmic-functions (FREE)
Question 998682: solve for x
x= 6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)
I am not sure how to find X, I would appreciate if someone can help me. I will provide my step.
x=6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)
=6/8 (log(base6) sqrt(108)/ (2/sqrt3) + log(base 6) 9^2 + log(base6) 64)
=6/8 (log(base6) sqrt(108) / (2/sqrt3) + log(base 6) (81)(64)
=6/8 (log(base6) 9 + log(base6) 5184)
=6/8 (log(base6) (9)(5184)
=6/8 (log(base6) 46656)
= log(base6) 34992
Click here to see answer by greenestamps(13367)   |
Question 998682: solve for x
x= 6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)
I am not sure how to find X, I would appreciate if someone can help me. I will provide my step.
x=6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)
=6/8 (log(base6) sqrt(108)/ (2/sqrt3) + log(base 6) 9^2 + log(base6) 64)
=6/8 (log(base6) sqrt(108) / (2/sqrt3) + log(base 6) (81)(64)
=6/8 (log(base6) 9 + log(base6) 5184)
=6/8 (log(base6) (9)(5184)
=6/8 (log(base6) 46656)
= log(base6) 34992
Click here to see answer by MathTherapy(10858)  |
Question 1157957: The population of Plano, Texas, which follows the exponential growth model, increased from
222,030 in 2000 to 259,841 in 2010. (Source: U.S. Census Bureau, www.census.gov)
Work is required!
a. Find the exponential growth rate, k. Give the exact rate.
b. Write the exponential growth function that models the population after t years.
c. What is the projected population in 2020?
d. How long should it take the population to double?
Click here to see answer by KMST(5402)  |
Question 289033: Hello,
I am having trouble with this question - could you please provide me with the steps, and solution?
If the half-life of Carbon 14 is 5730 years, how muc will remain of an initial 3 gms after 1000 years?
Thanks!
Click here to see answer by ikleyn(53944)  |
Question 1149061: Abby opened a retirement account with 9% APR and initial deposit of $8,000 compounded monthly.
(a) Find the exponential function that models the value of Abby's retirement account after t years.
(b) How long will it take to double the initial value? Estimate your answer to the nearest year.
(c) How long will it take to triple the initial value? Estimate your answer to the nearest year.
(d) How long will it take for the value of the account to reach 7 times the value of the account after 2 years?
Click here to see answer by MathTherapy(10858) |
Question 1104549: Please help me solve this word problem: in 1997, there were a total of 1,316,999 bankruptcies filed under the Bankruptcy Reform Act. The model for the number of bankruptcies filed is B(t)=0.798*1.164^t, where t is the number of years since 1994 and B is the number of bankruptcies filed in terms of millions (administrative office in US courts, statistical tables for the federal judiciary). In what year is it predicted that 12 million bankruptcies will be filed?
Click here to see answer by ikleyn(53944) |
Question 1104549: Please help me solve this word problem: in 1997, there were a total of 1,316,999 bankruptcies filed under the Bankruptcy Reform Act. The model for the number of bankruptcies filed is B(t)=0.798*1.164^t, where t is the number of years since 1994 and B is the number of bankruptcies filed in terms of millions (administrative office in US courts, statistical tables for the federal judiciary). In what year is it predicted that 12 million bankruptcies will be filed?
Click here to see answer by josgarithmetic(39838) |
Question 1104549: Please help me solve this word problem: in 1997, there were a total of 1,316,999 bankruptcies filed under the Bankruptcy Reform Act. The model for the number of bankruptcies filed is B(t)=0.798*1.164^t, where t is the number of years since 1994 and B is the number of bankruptcies filed in terms of millions (administrative office in US courts, statistical tables for the federal judiciary). In what year is it predicted that 12 million bankruptcies will be filed?
Click here to see answer by MathTherapy(10858) |
Question 280462: This one looked easy but it's got me confused please help and thank you.
Use the laws of logarithms to express log base2 6 - log base 2 3 + 2 log base 2 sqrt8 as a single logarithm then evaluate. I got this far log base 2^6 - log base2^3 +2 log base 2 sqrt 8 =log base 2 6/3 sqrt8^2??? help
Click here to see answer by greenestamps(13367) |
Question 280462: This one looked easy but it's got me confused please help and thank you.
Use the laws of logarithms to express log base2 6 - log base 2 3 + 2 log base 2 sqrt8 as a single logarithm then evaluate. I got this far log base 2^6 - log base2^3 +2 log base 2 sqrt 8 =log base 2 6/3 sqrt8^2??? help
Click here to see answer by MathTherapy(10858) |
Question 718152: Please help me solve for A and B in this exponential decay model y= ae^-bx. I have the following points: when x=0.6, y=1000 and when x=1.8, y=1.
I have done the following but I am not convienced it is the right path...
y=ae-bx therefor e-bx=y/a ... take log e of both sides ... loge e-bx = loge y/a
but logee=1 therefor -bx=loge y/a ... move the x over to get -b=x loge y/a
then enter values for x and y from example 1... -b= (0.6) loge(1000/a)
Is this the correct path to take for solving this?? Any advice would be greafull appreciated. Thank you.
Click here to see answer by greenestamps(13367) |
Question 718152: Please help me solve for A and B in this exponential decay model y= ae^-bx. I have the following points: when x=0.6, y=1000 and when x=1.8, y=1.
I have done the following but I am not convienced it is the right path...
y=ae-bx therefor e-bx=y/a ... take log e of both sides ... loge e-bx = loge y/a
but logee=1 therefor -bx=loge y/a ... move the x over to get -b=x loge y/a
then enter values for x and y from example 1... -b= (0.6) loge(1000/a)
Is this the correct path to take for solving this?? Any advice would be greafull appreciated. Thank you.
Click here to see answer by MathTherapy(10858) |
Question 31666: Oh this logarithm problems are killing me :)
Can you help! Write hte logarithm of a single expression:
log[b]6x+4(log[b]x-log[b]y)
(A) log[b] 6x^5/y^4
(B) log [b] 24x^2/y
(C) log [b] 10x/4y
(D) none of these.
Do we even consider the "B" in this expression?
Click here to see answer by MathTherapy(10858) |
Question 47675: Logarithms:
a) Using a calculator, find log 1000 where log means log to the base of 10.
Answer:
b) Most calculators have 2 different logs on them: log, which is base 10, and ln, which is base e. In computer science, digital computers are based on the binary numbering system which means that there are only 2 numbers available to the computer, 0 and 1. When a computer scientist needs a logarithm, he needs a log to base 2 which is not on any calculator. To find the log of a number to any base, we can use a conversion formula as shown here:
Using this formula,a=log a/log b, find log2 1000 . Round your answer to the hundredth's place.
Answer:
Show work in this space.
Click here to see answer by MathTherapy(10858) |
Question 253889: beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 240 g of beryllium-11 to decompose into 7.5g of beryllium-11?
based on the forumula provided in the text book C(t)=C(0)2e^-t/h
where C(0) = 240, C(t)=7.5 ,h=13.8
7.5/240=2e^-t/13.8
this was a s far as i got
Click here to see answer by ikleyn(53944) |
Question 253874: beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 240 g of beryllium-11 to decompose into 7.5g of beryllium-11?
based on the forumula provided in the text book C(t)=C(0)2e^-t/h
where C(0) = 240, C(t)=7.5 ,h=13.8
7.5/240=2e^-t/13.8
this was a s far as i got
Click here to see answer by ikleyn(53944) |
Question 730115: Berlyium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 2400g of berlyium-11 to decompose into 75g of berlyium-11?
Thats the question, and I tried solving it but im stuck. This is what I have so far:
75=2400 x 2^-t/13.8
0.01325=27.6 (-t)
Click here to see answer by ikleyn(53944) |
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