SOLUTION: My problem is written as; I had to name the property in each step. The first step they switched the x, so I think it's symmetric. step 2, the x came to be on the outsid and I'm thi
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-> SOLUTION: My problem is written as; I had to name the property in each step. The first step they switched the x, so I think it's symmetric. step 2, the x came to be on the outsid and I'm thi
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Question 98979: My problem is written as; I had to name the property in each step. The first step they switched the x, so I think it's symmetric. step 2, the x came to be on the outsid and I'm thinking that's reflexive. I need help on these steps bcause they are confusing.
x(y+1)+(-1)x = x(y+1)+x(-1)
= x [(y+1)]+(-1)]
= x[y+(1+ (-1))]
= x [y+0]
= xy Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! x(y+1)+(-1)x = x(y+1)+x(-1)
commutative: (-1)x=x(-1)
------------------
= x [(y+1)]+(-1)]
distributive
-----------------
= x[y+(1+ (-1))]
associative
-----------------
= x [y+0]
additive inverse
-------------------
= xy
additive identity
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Cheers,
Stan H.
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