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Question 838110: Hello, I need your guys help, and I'm sorry if I'm in the wrong place!
Ok, the problem is this: 2d = 3/2d +9.
In the book, it changed that problem into this...4d = 3d + 18. I'm having trouble figuring out how did 2d=3/2d+9 turn into 4d=3d+18.
The only way I can think of is to multiply everything by 2, but why??? Wouldn't the first step to this problem is to put "d" by it self or something? I already know what to do with "4d=3d+18" to get an answer. The only thing I'm having trouble is how did 2d=3/2d+9 turn into 4d=3d+18
Found 2 solutions by richard1234, MathTherapy:
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! Multiply both sides by 2, because fractions are annoying. You can also subtract (3/2)d from both sides to get (1/2)d = 9 --> d = 18, which is also a perfectly valid solution.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Hello, I need your guys help, and I'm sorry if I'm in the wrong place!
Ok, the problem is this: 2d = 3/2d +9.
In the book, it changed that problem into this...4d = 3d + 18. I'm having trouble figuring out how did 2d=3/2d+9 turn into 4d=3d+18.
The only way I can think of is to multiply everything by 2, but why??? Wouldn't the first step to this problem is to put "d" by it self or something? I already know what to do with "4d=3d+18" to get an answer. The only thing I'm having trouble is how did 2d=3/2d+9 turn into 4d=3d+18
The best way to approach this problem is to ELIMINATE the fraction,  . We began with: 
 ------- Multiplying both sides by 2 to get rid of the fraction,
4d = 3d + 18
Now you should be able to solve for d
Then do a check!!
If you need a complete and detailed solution, let me know!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
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