SOLUTION: the question says solve the equation -5(x+2)-5=-4(x-3) I distributed the -5 and the -4 but i can not remember how to do the rest?

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: the question says solve the equation -5(x+2)-5=-4(x-3) I distributed the -5 and the -4 but i can not remember how to do the rest?      Log On


   

Question 586401: the question says solve the equation -5(x+2)-5=-4(x-3) I distributed the -5 and the -4 but i can not remember how to do the rest?
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
-5%28x%2B2%29-5=-4%28x-3%29
-5x-10-5=-4x%2B12 Move the terms with x to the left, without x to the right side of the equation
-5x%2B4x=12%2B10%2B5
-x=27 divide by -1
x=-27