SOLUTION: Factor. I can check by multiplying, but get stuck figuring out the GCF and then applying that to each part. I think I have been looking at it too long?! 5x^7y^5+30x^5y^4+35xy

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Factor. I can check by multiplying, but get stuck figuring out the GCF and then applying that to each part. I think I have been looking at it too long?! 5x^7y^5+30x^5y^4+35xy      Log On


   



Question 466465: Factor. I can check by multiplying, but get stuck figuring out the GCF and then applying that to each part. I think I have been looking at it too long?!
5x^7y^5+30x^5y^4+35xy

Found 2 solutions by stanbon, ccs2011:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5x^7y^5+30x^5y^4+35xy
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GCF: 5xy
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Factor:
5xy[x^6y^4 + 6x^4y^3 +7]
===========================
Cheers,
Stan H.
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Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
5x%5E7y%5E5+%2B+30x%5E5y%5E4+%2B+35xy
The GCF is the greatest factor that each term has in common
Split it into parts:
GCF of coefficients 5,30,35 is 5
5/5 = 1
30/5 = 6
35/5 = 7
GCF of x^7, x^5, x is x
x%5E7%2Fx+=+x%5E6
x%5E5%2Fx+=+x%5E4
x%2Fx+=+1
GCF of y^5, y^4, y is y
y%5E5%2Fy+=+y%5E4
y%5E4%2Fy+=+y%5E3
y%2Fy+=+1
Put it together, the GCF = 5xy
Divide each term by 5xy
5xy%28x%5E6y%5E4+%2B+6x%5E4y%5E3+%2B+7%29