You can
put this solution on YOUR website!
Maybe do it this slightly different way:
-5d - 24 = -4(d + 6) - d
-5d - 24 = -4d - 24 - d
-5d - 24 = -5d - 24
-5d + 5d = -24 + 24
0d = 0
You can substitute any number for d in
that equation and it will always be a
solution since zero times any number
always equals 0.
So the anwer is "c. all numbers".
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But you could do it your way.
From your result
1d = 1d
you could tell that no matter what you
substituted for d, it would always check.
For instance if you substitute (2) for d
1d = 1d
1(2) = 1(2)
2 = 2
That checks.
If you substitute (-3) for d
1d = 1d
1(-3) = 1(-3)
-3 = -3
That checks.
You have the same thing on both sides of the equation
with your
1d = 1d
So any number you substitute on either side will have
to give you the same result on the other side.
Edwin