SOLUTION: How do you factor c^2-6c(a-c)+9(a-c)^2? I keep coming up with (3a-4c)^2 but the answer book says I am wrong.

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: How do you factor c^2-6c(a-c)+9(a-c)^2? I keep coming up with (3a-4c)^2 but the answer book says I am wrong.      Log On


   

Question 340330: How do you factor c^2-6c(a-c)+9(a-c)^2? I keep coming up with (3a-4c)^2 but the answer book says I am wrong.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
c%5E2-6c%28a-c%29%2B9%28a%5E2-2ac%2Bc%5E2%29=c%5E2-6ca%2B6c%5E2%2B9a%5E2-18ac%2B9c%5E2
c%5E2-6c%28a-c%29%2B9%28a%5E2-2ac%2Bc%5E2%29=16c%5E2-24ca%2B9a%5E2
c%5E2-6c%28a-c%29%2B9%28a%5E2-2ac%2Bc%5E2%29=%284c-3a%29%5E2
I get the same answer.
Something's up with your book.