SOLUTION: multiply (-5x^2+4y)(5x^2+5y+z) a. -25x^4-5x^2y^2+20y^2 b. -25x^2-5xy-5x^2z+20y^2+4z c. -25x^4-5x^2y+20y^4-5x^2yz d. -25x^4-5x^2y-5x^2z+20^2+4yz ^means to the power of....than

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: multiply (-5x^2+4y)(5x^2+5y+z) a. -25x^4-5x^2y^2+20y^2 b. -25x^2-5xy-5x^2z+20y^2+4z c. -25x^4-5x^2y+20y^4-5x^2yz d. -25x^4-5x^2y-5x^2z+20^2+4yz ^means to the power of....than      Log On


   

Question 336030: multiply
(-5x^2+4y)(5x^2+5y+z)
a. -25x^4-5x^2y^2+20y^2
b. -25x^2-5xy-5x^2z+20y^2+4z
c. -25x^4-5x^2y+20y^4-5x^2yz
d. -25x^4-5x^2y-5x^2z+20^2+4yz
^means to the power of....thanks
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28-5x%5E2%2B4y%29%285x%5E2%2B5y%2Bz%29 Start with the given expression.


-5x%5E2%285x%5E2%2B5y%2Bz%29%2B4y%285x%5E2%2B5y%2Bz%29 Expand.


Distribute.


-25x%5E4-25x%5E2y-5x%5E2z%2B20x%5E2y%2B20y%5E2%2B4yz Multiply.


-25x%5E4-5x%5E2y-5x%5E2z%2B20y%5E2%2B4yz Now combine like terms.


So %28-5x%5E2%2B4y%29%285x%5E2%2B5y%2Bz%29 expands to -25x%5E4-5x%5E2y-5x%5E2z%2B20y%5E2%2B4yz.


In other words, %28-5x%5E2%2B4y%29%285x%5E2%2B5y%2Bz%29=-25x%5E4-5x%5E2y-5x%5E2z%2B20y%5E2%2B4yz.


So the answer looks like it is D) (assuming you forgot the 'y')


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my website.

Jim