SOLUTION: Factor completely thankyou 64a^3-27b^3 a. (4a-3b)(16a^2+9b^2) b. (4a+3b^2)(16a^2-12ab+9b^2) c. (64a-3b)(a^2+12ab+9b^2) d. (4a-3b)(16a^2+12ab+9b^2) ps the ^ button means power

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Factor completely thankyou 64a^3-27b^3 a. (4a-3b)(16a^2+9b^2) b. (4a+3b^2)(16a^2-12ab+9b^2) c. (64a-3b)(a^2+12ab+9b^2) d. (4a-3b)(16a^2+12ab+9b^2) ps the ^ button means power      Log On


   

Question 336005: Factor completely thankyou
64a^3-27b^3
a. (4a-3b)(16a^2+9b^2)
b. (4a+3b^2)(16a^2-12ab+9b^2)
c. (64a-3b)(a^2+12ab+9b^2)
d. (4a-3b)(16a^2+12ab+9b^2)
ps the ^ button means power ....example to the power of 3 thanks
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

64a%5E3-27b%5E3 Start with the given expression.


%284a%29%5E3-%283b%29%5E3 Rewrite 64a%5E3 as %284a%29%5E3. Rewrite 27b%5E3 as %283b%29%5E3.


%284a-3b%29%28%284a%29%5E2%2B%284a%29%283b%29%2B%283b%29%5E2%29 Now factor by using the difference of cubes formula. Remember the difference of cubes formula is A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29


%284a-3b%29%2816a%5E2%2B12ab%2B9b%5E2%29 Multiply

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Answer:
So 64a%5E3-27b%5E3 factors to %284a-3b%29%2816a%5E2%2B12ab%2B9b%5E2%29.

In other words, 64a%5E3-27b%5E3=%284a-3b%29%2816a%5E2%2B12ab%2B9b%5E2%29


So the answer is D)


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Jim