SOLUTION: reverse foil or grouping 2x^2+15x+25

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Question 299373: reverse foil or grouping
2x^2+15x+25

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 2x%5E2%2B15x%2B25, we can see that the first coefficient is 2, the second coefficient is 15, and the last term is 25.


Now multiply the first coefficient 2 by the last term 25 to get %282%29%2825%29=50.


Now the question is: what two whole numbers multiply to 50 (the previous product) and add to the second coefficient 15?


To find these two numbers, we need to list all of the factors of 50 (the previous product).


Factors of 50:
1,2,5,10,25,50
-1,-2,-5,-10,-25,-50


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 50.
1*50 = 50
2*25 = 50
5*10 = 50
(-1)*(-50) = 50
(-2)*(-25) = 50
(-5)*(-10) = 50

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 15:


First NumberSecond NumberSum
1501+50=51
2252+25=27
5105+10=15
-1-50-1+(-50)=-51
-2-25-2+(-25)=-27
-5-10-5+(-10)=-15



From the table, we can see that the two numbers 5 and 10 add to 15 (the middle coefficient).


So the two numbers 5 and 10 both multiply to 50 and add to 15


Now replace the middle term 15x with 5x%2B10x. Remember, 5 and 10 add to 15. So this shows us that 5x%2B10x=15x.


2x%5E2%2Bhighlight%285x%2B10x%29%2B25 Replace the second term 15x with 5x%2B10x.


%282x%5E2%2B5x%29%2B%2810x%2B25%29 Group the terms into two pairs.


x%282x%2B5%29%2B%2810x%2B25%29 Factor out the GCF x from the first group.


x%282x%2B5%29%2B5%282x%2B5%29 Factor out 5 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B5%29%282x%2B5%29 Combine like terms. Or factor out the common term 2x%2B5


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Answer:


So 2x%5E2%2B15x%2B25 factors to %28x%2B5%29%282x%2B5%29.


In other words, 2x%5E2%2B15x%2B25=%28x%2B5%29%282x%2B5%29.


Note: you can check the answer by expanding %28x%2B5%29%282x%2B5%29 to get 2x%5E2%2B15x%2B25 or by graphing the original expression and the answer (the two graphs should be identical).