SOLUTION: 2w2-5-=9w quadric equation i can't factor ? 2w2[w is squared]. 2w2-5-9w=9w-9w, so 2w2-5-9w=0 wher do i go from here? all must = 0 thanks if you can help sue

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: 2w2-5-=9w quadric equation i can't factor ? 2w2[w is squared]. 2w2-5-9w=9w-9w, so 2w2-5-9w=0 wher do i go from here? all must = 0 thanks if you can help sue      Log On


   

Question 299264: 2w2-5-=9w quadric equation i can't factor ? 2w2[w is squared]. 2w2-5-9w=9w-9w, so 2w2-5-9w=0 wher do i go from here? all must = 0 thanks if you can help sue
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
2w%5E2-5+=+9w Subtract 9w from both sides.
2w%5E2-9w-5+=+0 Factor.
%282w%2B1%29%28w-5%29+=+0 Apply the "zero product" rule.
2w%2B1+=+0 or w-5+=+0 so...
2w+=+-1 or w+=+5
highlight%28w+=+-1%2F2%29 or highlight%28w+=5%29