SOLUTION: Hello wonderful ones. I have yet another problem. How would you factor 3x^2+22xy+24y^2 Your help is so appreciated.

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Hello wonderful ones. I have yet another problem. How would you factor 3x^2+22xy+24y^2 Your help is so appreciated.      Log On


   



Question 176941: Hello wonderful ones. I have yet another problem.
How would you factor
3x^2+22xy+24y^2
Your help is so appreciated.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at 3x%5E2%2B22xy%2B24y%5E2 we can see that the first term is 3x%5E2 and the last term is 24y%5E2 where the coefficients are 3 and 24 respectively.

Now multiply the first coefficient 3 and the last coefficient 24 to get 72. Now what two numbers multiply to 72 and add to the middle coefficient 22? Let's list all of the factors of 72:



Factors of 72:
1,2,3,4,6,8,9,12,18,24,36,72

-1,-2,-3,-4,-6,-8,-9,-12,-18,-24,-36,-72 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 72
1*72
2*36
3*24
4*18
6*12
8*9
(-1)*(-72)
(-2)*(-36)
(-3)*(-24)
(-4)*(-18)
(-6)*(-12)
(-8)*(-9)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 22? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 22

First NumberSecond NumberSum
1721+72=73
2362+36=38
3243+24=27
4184+18=22
6126+12=18
898+9=17
-1-72-1+(-72)=-73
-2-36-2+(-36)=-38
-3-24-3+(-24)=-27
-4-18-4+(-18)=-22
-6-12-6+(-12)=-18
-8-9-8+(-9)=-17



From this list we can see that 4 and 18 add up to 22 and multiply to 72


Now looking at the expression 3x%5E2%2B22xy%2B24y%5E2, replace 22xy with 4xy%2B18xy (notice 4xy%2B18xy adds up to 22xy. So it is equivalent to 22xy)

3x%5E2%2Bhighlight%284xy%2B18xy%29%2B24y%5E2


Now let's factor 3x%5E2%2B4xy%2B18xy%2B24y%5E2 by grouping:


%283x%5E2%2B4xy%29%2B%2818xy%2B24y%5E2%29 Group like terms


x%283x%2B4y%29%2B6y%283x%2B4y%29 Factor out the GCF of x out of the first group. Factor out the GCF of 6y out of the second group


%28x%2B6y%29%283x%2B4y%29 Since we have a common term of 3x%2B4y, we can combine like terms

So 3x%5E2%2B4xy%2B18xy%2B24y%5E2 factors to %28x%2B6y%29%283x%2B4y%29


So this also means that 3x%5E2%2B22xy%2B24y%5E2 factors to %28x%2B6y%29%283x%2B4y%29 (since 3x%5E2%2B22xy%2B24y%5E2 is equivalent to 3x%5E2%2B4xy%2B18xy%2B24y%5E2)



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Answer:
So 3x%5E2%2B22xy%2B24y%5E2 factors to %28x%2B6y%29%283x%2B4y%29