|
Question 168786: I asked the same question ealier and got an answer to try it instead of helping. Can someone please help me find what I am doing wrong.
y^2-6y+9
I got(y-3)^2 but I dont come out to the same thing when I plug in the answer I dont get the +9. I also came up with(y+3)^2 but still dont get -6y.
Answer by Electrified_Levi(103)   (Show Source):
You can put this solution on YOUR website! Hi, Hope I can help,
.
If you are wanting us to solve this quadratic equation, here is how you do it.
.
.
The easiest way you can solve this is by factoring, in this case we can
.
First we need to write the "y"'s in parentheses
.
It is only "y" squared so there will be two "y"'s
.
( y )(y )
.
Next, we need to find the rest of the factors of this quadratic
.
If the factors of the third term, in this case "9", add up to the middle term( in this case (-6)), it can be factored
.
factors of "9" added together
.
(9) + (1) = 10
.
(-9) + (-1) = (-10)
.
(3) + (3) = 6
.
(-3) + (-3) = (-6)
.
The last pair of factors add up to the middle term
.
Now we will put the factors in the parentheses with the "y"'s
.
( y )(y ) = (y - 3 )(y - 3 )
.
This is the factored quadratic
.
( y - 3 )(y - 3 ) = 0, you can check by using the FOIL method ( First, Inner, Outer, Last )
.
 = (F)  = (O)  = (I)  = (L)  , Remember the negative signs on the "3's"
.
 , combine the like terms,  (forget about the multiplication sign, it is just being weird) =  ( True )
.
now we take each of the factors and have them equal "0", then solve for "y"
.
First factor = ( y - 3 )
.
 , removing the parentheses
.
 , moving (-3) to the right side
.
 = 
.
, the other factor is the same, so we would get the same answer.
.
your answer is , you can check by replacing "y" with "3" in the original equation
.
 =  =  =  =  ( True )
.
You can also use the quadratic formula, for every quadratic equation, make sure your equation is in the form  ( in this case "y" ) it is
.
.
a = 1
.
b = -6
.
c = 9
.
 =  =  =  =  =  = 
.
Your answer is
.
Hope I helped, Levi
|
|
|
| |
