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Question 1150882: linda invested 12,000 for one year, part at 12 percent annual interest and the rest at 6 percent annual interest. how much did she invest at 6 percent to get 1,200 interest in a year
Answer by ikleyn(52767)   (Show Source):
You can put this solution on YOUR website! .
Let x be the amount Linda invested at 6%.
Then the amount she invested at 12% is (12000-x).
The annual interest of the 6% investment is 0.06x.
The annual interest of the 6% investment is 0.12(12000-x).
The total interest is the sum of partial interests, which gives you this basic setup equation
0.06x + 0.12*(12000-x) = 1200.
From the equation,
x =  = 4000.
ANSWER. The amount invested at 6% is 4000.
CHECK. 0.06*4000 + 0.12*(12000-4000) = 1200. ! Precisely correct !
Solved.
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It is a standard and typical problem on investments.
If you need more details, or if you want to see other similar problems solved by different methods, look into the lesson
- Using systems of equations to solve problems on investment
in this site.
You will find there different approaches (using one equation or a system of two equations in two unknowns), as well as
different methods of solution to the equations (Substitution, Elimination).
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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