SOLUTION: My question is more about what rule to follow than calculations
8÷2(2+2)
Do you use order of execution rules to solve
8÷2(2+2)=8÷2(4)=8÷2×4=4×4=16
Or do you use distri
Question 1143620: My question is more about what rule to follow than calculations
8÷2(2+2)
Do you use order of execution rules to solve
8÷2(2+2)=8÷2(4)=8÷2×4=4×4=16
Or do you use distributive law to solve
8÷2(2+2)=8÷(2×2+2×2)=8÷(4+4)=8÷8=1
Which answer is right and why and which answer is wrong and why
You can put this solution on YOUR website! My question is more about what rule to follow than calculations
8÷2(2+2)
Do you use order of execution rules to solve
8÷2(2+2)=8÷2(4)=8÷2×4=4×4=16
Or do you use distributive law to solve
8÷2(2+2)=8÷(2×2+2×2)=8÷(4+4)=8÷8=1
Which answer is right and why and which answer is wrong and why
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Remember PEMDAS
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Parentheses
Exponents
Multiply
Divide
Add
Subtract
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8÷2(2+2) is ambiguous, should be either 8÷(2(2+2)) or (8÷2)(2+2), so an argument can be made to support either "answer."
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If it's 8÷(2(2+2))
--> 8÷(2*4)
= 8/8 = 1
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Notice I did say "if"
The above answer is wrong.
We cannot use the distributive law.
We must use the rule of PE(MD)(AS) or
We do what's in the parentheses first.
Since 2+2 is in the parentheses, we must do that first,
and get 4. So we replace 2+2 by 4. Now we have:
8÷2(4)
Now there is nothing to do in the parentheses.
There are no exponents.
We look for the first multiplication or division going left to right.
(Neither multiplication nor division necessarily comes before the
other, we must do whichever one comes first going left to right.
That's 8÷2. So we do that and get 4. So we replace 8÷2 by 4
4(4)
There is nothing to do in the parentheses, and there is only the
multiplication 4(4) left, so the final answer is
16.
Edwin
