SOLUTION: Consider the function f(x) = 2x + 5 √x^2-1 (x^2-1 is all under the squareroot). Find f(5), f(a), f(x + h).

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Consider the function f(x) = 2x + 5 √x^2-1 (x^2-1 is all under the squareroot). Find f(5), f(a), f(x + h).      Log On


   

Question 1133180: Consider the function f(x) = 2x + 5 √x^2-1 (x^2-1 is all under the squareroot).
Find f(5), f(a), f(x + h).
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
f(5)=10+5(sqrt(24) or 10+10*sqrt(6) or 10(1+ sqrt(6))
f(a)=2a+5(sqrt(a^2-1))
f(x+h)=2x+2h+5* sqrt(x^2+2xh+h^2-1)