SOLUTION: Pls help me solve this, What quadrant is the vertex of {{{ f(x)=-3(x-2)^2+6 }}} in?

Algebra ->  Coordinate-system -> SOLUTION: Pls help me solve this, What quadrant is the vertex of {{{ f(x)=-3(x-2)^2+6 }}} in?      Log On


   

Question 976494: Pls help me solve this,
What quadrant is the vertex of +f%28x%29=-3%28x-2%29%5E2%2B6+ in?
Found 2 solutions by jim_thompson5910, solver91311:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
+f%28x%29=-3%28x-2%29%5E2%2B6+ is the same as +y=-3%28x-2%29%5E2%2B6+ which is in the form +y=a%28x-h%29%5E2%2Bk+

here we see that
a = -3
h = 2
k = 6

The vertex is (h,k) = (2,6) which is in quadrant 1
------------------------------------------------------------------------------------------------------------------------

If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).

Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.

Jim
------------------------------------------------------------------------------------------------------------------------

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


You can read the coordinates of the vertex directly from your vertex form equation. Determine the quadrant by examining the signs on your vertex coordiantes:

Q I: +, +
Q II: -, +
Q III: -, -
Q IV: +, -

John

My calculator said it, I believe it, that settles it