SOLUTION: what is the vertex of parabola of y=x^2+4x+7

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Question 759885: what is the vertex of parabola of y=x^2+4x+7
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
y = x^2 + 4x + 7
Complete the square
x^ + 4x +7
(4/2)^2
x^2 + 4x + 4 -4 + 7
(x + 2)^2 +3
vertex = (-2,3)
Hope this helps.
:-)