SOLUTION: Determine the equation of the line with slope -2/3 and passes through the point (-6, 3). Express the equation of the line in both slope–intercept form and standard form.

Algebra ->  Coordinate-system -> SOLUTION: Determine the equation of the line with slope -2/3 and passes through the point (-6, 3). Express the equation of the line in both slope–intercept form and standard form.       Log On


   

Question 752582: Determine the equation of the line with slope -2/3 and passes through the point (-6, 3).
Express the equation of the line in both slope–intercept form and standard form.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Determine the equation of the line with slope -2/3 and passes through
the point (-6, 3).
Express the equation of the line in both slope–intercept form
:
Use the point point/slope formula: y - y1 = m(x - x1)
y - 3 = -2%2F3(x - (-6))
y - 3 = -2%2F3(x + 6)
y - 3 = -2%2F3x - 4
y = -2%2F3x - 4 + 3
y = -2%2F3x - 1; the slope/intercept form
:
Find the standard form
y = -2%2F3x - 1
2%2F3x + y - 1
get rid of the denominator, mult by 3, resulting in:
2x + 3y = -3
:
:
Check solutions by replacing x and y with -6 and 3
2(-6) + 3(3) = -3