Hi, (3,x) (2 ,-1) (x+1)^2 + 1^2 = 13^2 x^2 + 2x + 1 = 169 x^2 +2x - 168 = 0 (x + 14)(x-12) = 0 x = -14 0r x = 12 Find all the points having an x-coordinate of 3 whose distance from the point (-2, -1) is 13 Pt(3,-14) and Pt(3,12)