SOLUTION: Give the coordinates of the vertex and graph the coordinates of the parabola? y=x^2+2x+4 I know the vertex is (-1,3) and I can easily plot that on the graph but what is the o

Algebra ->  Coordinate-system -> SOLUTION: Give the coordinates of the vertex and graph the coordinates of the parabola? y=x^2+2x+4 I know the vertex is (-1,3) and I can easily plot that on the graph but what is the o      Log On


   

Question 621126: Give the coordinates of the vertex and graph the coordinates of the parabola?
y=x^2+2x+4
I know the vertex is (-1,3) and I can easily plot that on the graph but what is the other point I have to plot in order to graph the parabola? I'm having a hard time with the graphing part.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

y=x^2+2x+4   Note:  (0,4)is where Parabola crosses the y axis

y = (x+1)^2 -1 + 4

y+=+1%2A%28x%2B1%29%5E2+%2B3   V(-1,3) Yes!  Important 1st Step

For graphing:

2nd step: Which direction does the Parabola Open? 

 y = a(x-h)^2 + k   is the general form of a parabola opening Up or Down, a = 1 > 0, parabola opens Up

3rd Step:  what is the Line of symmetry:  x = -1

Plotting Vertex and y-intercept and putting in the line of symmetry,

 allows us to determine the graph