Question 568526: I'm trying to find the center, radius, & intercepts of the circle with the given equation.
x^2+y^2-16x+2y+49=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! I'm trying to find the center, radius, & intercepts of the circle with the given equation.
x^2+y^2-16x+2y+49=0
complete the squares
(x^2-16x+64)+(y^2+2y+1)=-49+64+1=16
(x-8)^2+(y+1)^2=16
center: (8,-1)
radius: √16=4
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to find x-intercepts, set y=0, then solve for x
x^2-16x+49=0
solving by following quadratic formula
a=1, b=-16, c=49
answers:
x≈4.13 and 11.90
..
To find y-intercepts, set x=0, then solve for y
y^2+2y+49=0
discriminant=b^2-4*a*c =2^2-4*1*49=-192<0
therefore, y-intercept: none
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