SOLUTION: i) Express {{{6 + 4x - x^2}}} in the form {{{a - (x + b)^2}}}, where a and b are integers. ii) Find the coordinates of the turning point of the curve {{{y = 6 + 4x - x^2}}} and de

Algebra ->  Coordinate-system -> SOLUTION: i) Express {{{6 + 4x - x^2}}} in the form {{{a - (x + b)^2}}}, where a and b are integers. ii) Find the coordinates of the turning point of the curve {{{y = 6 + 4x - x^2}}} and de      Log On


   

Question 473619: i) Express 6+%2B+4x+-+x%5E2 in the form a+-+%28x+%2B+b%29%5E2, where a and b are integers.
ii) Find the coordinates of the turning point of the curve y+=+6+%2B+4x+-+x%5E2 and determine the nature of this turning point.
*Please answer as soon as possible bro :)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

Find the coordinates of the turning point of the curve 

y+=+-x%5E2+%2B4x%2B6  |Turning point is the Vertex of the Parabola

  y = -[x^2 - 4x] + 6

  y = -[(x-2)^2 - 4] + 6

  y = -(x-2)^2 + 10  V(2,10), the turning point

       a = -1 -1<0, Parabola opens downward, turning point is a maximum