Question 385337: Find the equation of the line passing through the point (3,1) and parallel to the line which joins (3,-2) and (6,4).
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation of the line passing through the point (3,1) and parallel to the line which joins (3,-2) and (6,4).
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slope of the given line = (4--2)/(6-3) = 2
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Equation of line with slope = 2 passing thru (3,1).
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Form: y = mx + b
Substitute for y,x,m and solve for "b":
1 = 2*3+b
b = -5
Equation:
y = 2x-5
Cheers,
Stan H.
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