SOLUTION: Graph this function. F(x) ((( -3x -1 if -6 is less than or equal to x is less than equal to -4 -1/4 is less than x is less than or equal to 8. ( I tried plugging in those

Algebra ->  Coordinate-system -> SOLUTION: Graph this function. F(x) ((( -3x -1 if -6 is less than or equal to x is less than equal to -4 -1/4 is less than x is less than or equal to 8. ( I tried plugging in those       Log On


   

Question 1205632: Graph this function. F(x) ((( -3x -1 if -6 is less than or equal to x is less than equal to -4 -1/4 is less than x is less than or equal to 8. ( I tried plugging in those numbers … ie. -3 x -6,-5,-4 minus 1. Is that how you solve this ?
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

It appears you're trying to graph a piecewise function. The first part appears to be -3x-1 when -6+%3C=+x+%3C=+-4

The second part seems to be missing. You wrote -1%2F4+%3C+x+%3C=+8 but forgot about the expression for this domain restriction.

In short, what you posted is incomplete. Please revise carefully. I recommend writing the piecewise function as separate lines.

Example:
-3x-1 when -6+%3C=+x+%3C=+-4
5x+7 when -1%2F4+%3C+x+%3C=+8
Replace the stuff in red with your actual expression.


Despite the fact I cannot answer this question fully, I can help with the first part.
-3x-1 when -6+%3C=+x+%3C=+-4 means we'll graph y = -3x-1 for that interval mentioned.
The graph of y = -3x-1 is a straight line through (0,-1) and (1,-4).
Here's the scratch work proving that x = 1 leads to y = -4.
y = -3x-1
y = -3*1-1
y = -3-1
y = -4
Similar steps are applied when x = 0.

After drawing a straight line through (0,-1) and (1,-4), erase the portions to the left of x = -6 and to the right of x = -4.
What results is a segment with endpoints (-6,17) and (-4,11)

I used Desmos to graph. GeoGebra is another good alternative.