SOLUTION: Find an equation of the line containing the centers of the two circles whose equations are given below. (x-6)^2+(y-3)^2=49 (x+4)^2+(y-4)^2=81
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-> SOLUTION: Find an equation of the line containing the centers of the two circles whose equations are given below. (x-6)^2+(y-3)^2=49 (x+4)^2+(y-4)^2=81
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Question 1202856: Find an equation of the line containing the centers of the two circles whose equations are given below. (x-6)^2+(y-3)^2=49 (x+4)^2+(y-4)^2=81 Found 2 solutions by josgarithmetic, greenestamps:Answer by josgarithmetic(39617) (Show Source):
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line containing the centers of the two circles whose equations are given below. (x-6)^2+(y-3)^2=49 (x+4)^2+(y-4)^2=81
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line containing the centers of the two circles whose equations are given below. (x-6)^2+(y-3)^2=49, AND (x+4)^2+(y-4)^2=81
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The two points are (6, 3) and (-4, 4).
IF you already know how to find equation of a line through two given points, then you're all set knowing what to do.
Do you understand why this is or can be used?
In more detail,
Picking the point (6, 3) as build the variable slope expression
and both points for the slope value
(