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Question 117230: find the equation of the line perpendicular to  and passes through (-2,5)
Answer by misscrt(37)   (Show Source):
You can put this solution on YOUR website! find the equation of the line perpendicular to and passes through (-2,5)
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If the line is perpendicular,its slope will be the negative reciprocal of the original line's slope, m.
is in the form of equation of line----y=mx+b
So, the original line has a slop of -2/3
The negative reciprocal of -2/3 is 3/2.
So, the new line has slope,m=3/2
Since you are given the point which the new line goes through use the point-slope form to find its equation:
(x1,y1)=(-2,5)
(y-y1)=m(x-x1)
(y-5) = 3/2(x-(-2))
Put equation into the standard form,y=mx+b.
y=3x/2+3 +5
Hope that helps.
Regards,
misscrt
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