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Question 117206:
Write the equation of the line passing through (–6, –9) and (1, –9).
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! First lets find the slope through the points ( , ) and ( ,)
 Start with the slope formula (note: ) is the first point (,) and ) is the second point (,))
 Plug in  , , , (these are the coordinates of given points)
 Subtract the terms in the numerator  to get  . Subtract the terms in the denominator  to get 
 Reduce
So the slope is
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Now let's use the point-slope formula to find the equation of the line:
------Point-Slope Formula------
 where  is the slope, and ) is one of the given points
So lets use the Point-Slope Formula to find the equation of the line
 Plug in , , and (these values are given)
 Rewrite  as 
 Rewrite  as 
 Distribute
 Multiply and  to get  . Now reduce to get
 Subtract  from both sides to isolate y
 Combine like terms and to get
 Remove the zero term
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Answer:
So the equation of the line which goes through the points (,) and (,) is:
The equation is now in  form (which is slope-intercept form) where the slope is and the y-intercept is 
Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this solver)
 Graph of through the points (,) and (,)
Notice how the two points lie on the line. This graphically verifies our answer.
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! slope=(-9+9)/(1+6)
slope=(0/7)
slope=0
now replace the line formula [Y=mX+b]
-9=0*-6+b
b=-9
SO THE EQUATION IS Y=-9.
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, Y = -9).
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