Question 1161262: A line in the (x,y) coordinate plane contains the points P(x,7)and Q(1,1).
a) Given that the distance between the points P and Q is 10 units, what is the value of x?
b) Use your answer in (a) to find the midpoint of PQ.
Found 2 solutions by Boreal, MathLover1:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! That means the sqrt{ (diff in x)^2+ (diff in y)^2}=100
so (x-1)^2+6^2=100
x^2-2x+1+36=100
x^2-2x-63=0
(x-9)(x+7)=0
x=9 or x=-7
The points are (9, 7) and (1, 1) with midpoint (5, 4)
and (-7, 7) and (1, 1) with mid point (-3, 4)
Answer by MathLover1(20849)  (Show Source):
You can put this solution on YOUR website!
A line in the ( , ) coordinate plane contains the points
 (, ) and
 ( ,)
a)
Given that the distance between the points and is  units, what is the value of ?
use distance formula:
 ....plug in given points and distance
=>  or 
so, ( ,) or ( ,)
b)
Use your answer in (a) to find the midpoint of  .
if (,) and
(,)
the midpoint of is
 =( , )=( , )
or
if (,) and
(,)
=( ,)=( ,)
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