SOLUTION: The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
x – 4y =
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-> SOLUTION: The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
x – 4y =
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Question 1022730: The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2 Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12).
This statement is not true. Try substituting the first point, (-4,-3) into the equation. It does not form a solution.
