SOLUTION: This is a self written problem because I wanted to explore things myself, so here it is:
Given the two points P(0,1) and Q(3,4)
I solved for the slope, which was m= -1
I p
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-> SOLUTION: This is a self written problem because I wanted to explore things myself, so here it is:
Given the two points P(0,1) and Q(3,4)
I solved for the slope, which was m= -1
I p
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Question 1016661: This is a self written problem because I wanted to explore things myself, so here it is:
Given the two points P(0,1) and Q(3,4)
I solved for the slope, which was m= -1
I plugged that into the point-slope formula a received the slope-intercept equation of the line:
y=-x+1
but when I plug in the original points to see if they are actually part of the line, point Q(3,4) doesn't work.
I'm not sure why that happened. I see that point P(0,1) is actually where the graph crosses or touches the graph, but it doesn't make sense that point Q(3,4) isn't on the graph.
Any suggestions or help would be helpful.
Edit: I solved it. :) Answer by fractalier(6550) (Show Source):
