SOLUTION: I believe this is just invalid, can somebody confirm if that is the correct answer or does it match up with a property? INSTRUCTIONS: Determine whether the following symbolized

Algebra ->  Conjunction -> SOLUTION: I believe this is just invalid, can somebody confirm if that is the correct answer or does it match up with a property? INSTRUCTIONS: Determine whether the following symbolized      Log On


   



Question 975481: I believe this is just invalid, can somebody confirm if that is the correct answer or does it match up with a property?
INSTRUCTIONS: Determine whether the following symbolized arguments are valid or invalid by identifying the form of each. In some cases the argument must be rewritten using double negation or commutativity before it has a named form. Those arguments without a specific name are invalid.
(∼G ∨ E) • (R ∨ M)
R ∨ ∼G ___
E ∨ M

MT--valid.

Invalid.

DA--invalid.

MP--valid.

AC--invalid.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I call this one invalid.

Consider the case .

Both and are true, yet is nonetheless false.

John

My calculator said it, I believe it, that settles it