SOLUTION: Construct a truth table for the statement, (p <--->q) --->p Any help would be greatly appreciated. Or an example of a very similar problem with the exact same punctuations etc. Pl

Algebra ->  Conjunction -> SOLUTION: Construct a truth table for the statement, (p <--->q) --->p Any help would be greatly appreciated. Or an example of a very similar problem with the exact same punctuations etc. Pl      Log On


   

Question 729129: Construct a truth table for the statement, (p <--->q) --->p
Any help would be greatly appreciated. Or an example of a very similar problem with the exact same punctuations etc. Please help!!! Thank you
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Here's what the completed table looks like

Keep in mind that p <--> q is only true if BOTH p AND q have the same truth value (ie both are true or false together)

Also, p --> q is only false when p is true and q is false. Otherwise it's true.

p q p <--> q (p <--> q) --> p
T T T T
T F F T
F T F T
F F T F