SOLUTION: Truth Table: ~(P=>Q)<=>(P^~Q)
I believe I am on the right path with the following:
P Q P=>Q ~(P=>Q) ~Q P^~Q
t t t t f t
f t t
Algebra ->
Conjunction
-> SOLUTION: Truth Table: ~(P=>Q)<=>(P^~Q)
I believe I am on the right path with the following:
P Q P=>Q ~(P=>Q) ~Q P^~Q
t t t t f t
f t t
Log On
Question 385135: Truth Table: ~(P=>Q)<=>(P^~Q)
I believe I am on the right path with the following:
P Q P=>Q ~(P=>Q) ~Q P^~Q
t t t t f t
f t t f f f
t f f t t t
f f t f t f
Making this table a neither a tautology or a contrdiction. Would this be correct? Six columns with 4 t or f under each column. They would not line up for me so I hope this is understandable.
Melody
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