SOLUTION: (∼r ∨ ∼p) ∨ ∼q determnine if its valid or invalid A. p is true, q is false, r is true B. p is false, q is true, r is treu I have tried everyth

Algebra ->  Conjunction -> SOLUTION: (∼r ∨ ∼p) ∨ ∼q determnine if its valid or invalid A. p is true, q is false, r is true B. p is false, q is true, r is treu I have tried everyth      Log On


   

Question 355217: (∼r ∨ ∼p) ∨ ∼q
determnine if its valid or invalid
A. p is true, q is false, r is true
B. p is false, q is true, r is treu
I have tried everything and can't figure how to do logics. Any help will be greatly appreciated.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First generate the truth table, then you can pick out the answer from the row.
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r       p       q      -r      -p      -q    -r v -q    (-r v -p) v –q
-----------------------------------------------------------------------
T      	T	T	F	F	F	F                 F
T	T	F	F	F	T	F                 T
T	F	T	F	T	F	T                 T
T	F	F	F	T	T	T                 T
F	T	T	T	F	F	T                 T
F	T	F	T	F	T	T                 T
F	F	T	T	T	F	T                 T
F	F	F	T	T	T	T                 T