SOLUTION: How would I graph the circle x^2+ y^2-8x+6y+21=0

Question 951695: How would I graph the circle
x^2+ y^2-8x+6y+21=0
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How would I graph the circle
x^2+ y^2-8x+6y+21=0
Put the equation in center-radius form::
x^2 - 8x + 16 + y^2 + 6y + 9 = -21 + 16 + 9
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(x-4)^2 + (y+3)^2 = 4
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Center:: (4,-3)
Radius:: 2
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Draw a circle with center at (4,-3) and radius = 2
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Cheers,
Stan H.
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Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
to graph it, first write it in standard form where and are and coordinates of the center, and is a radius
....complete squares

so, and , the center is at (,)
and =>
plot a point (,) and draw a circle using

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