SOLUTION: What is the center and the radius of the circle: x^2+y^2-6y-16=0

Question 764444: What is the center and the radius of the circle:
x^2+y^2-6y-16=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the center and the radius of the circle:
x^2+y^2-6y-16=0
***
Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of the center, r=radius
x^2+y^2-6y-16=0
complete the square:
x^2+(y^2-6y+9)-9-16=0
x^2+(y-3)^2=25
center: (0,3)
radius=√25=5
RELATED QUESTIONS
what is the standard form, radius, and center of this circle equation:... (answered by Fombitz)

x^2+y^2+6x-6y-107=0 What is the Radius and Center of a circle (answered by Alan3354)

x^2 + y^2 - 2x + 6y - 3 = 0 (find center and radius of the... (answered by Edwin McCravy)

x^2+y^2-6y=0 Please find the center and the radius of the circle and graph... (answered by stanbon)

Find the center and the radius of the circle give by... (answered by Fombitz)

find the center and the radius of the circle... (answered by KnightOwlTutor)

find the center and the radius of the circle x^2+y^2-10x-6y+29=0. (answered by richwmiller)

Find the center and radius of the following circle:... (answered by Alan3354)

1.find the equation of the circle w/ center (1, 4) and radius 5. 2.find the equation of... (answered by Fombitz)