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ABCD is a square with side of 10 cm. Square PQRS is drawn inside the square ABCD
such that trapezoids PQBA, QRCB, SRCD and PSDA are equal.
If the area of the trapezoid is 16 cm^2, find the height of the trapezium.
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From the area of the square ABCD, subtract four times the area of the trapezoid to get the area of the square PQRS
the area of the square PQRS = 10^2 - 4*16 = 100 - 64 = 36 cm^2.
Hence, the side of the square PQRS is = 6.
Since the trapezoids are equal (congruent), it means that the strip between the squares is of uniform width of cm = = 2 cm.
The width of the strip is the height of the trapezoids.
ANSWER. The height of the trapezoids is 2 cm.
Solved.
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These words in the condition of the problem
Square PQRS
perplexed me, when I read this problem today in the morning . . .